Answered

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1. What is the slope of a line that is perpendicular to the line represented by the equation 3x + 4y = 12?

A. 3/4
B. -4/3
C. 4/3
D. -3/4

Sagot :

Answer:

C

Step-by-step explanation:

Given a line with slope m then the slope of a line perpendicular to it is

[tex]m_{perpendicular}[/tex] = - [tex]\frac{1}{m}[/tex]

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Given

3x + 4y = 12 ( subtract 3x from both sides )

4y = - 3x + 12 ( divide terms by 4 )

y = - [tex]\frac{3}{4}[/tex] x + 3 ← in slope- intercept form

with slope m = - [tex]\frac{3}{4}[/tex]

Then

[tex]m_{perpendicular}[/tex] = - [tex]\frac{1}{-\frac{3}{4} }[/tex] = [tex]\frac{4}{3}[/tex] → C

saanvichauhanos6
4/3 is the answer
Mark brainlist
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