Using the condition given to build an inequality, it is found that the maximum number of junior high school student he can still recruit is of 17.
Inequality:
Considering s the number of senior students and j the number of junior students, and that he cannot recruit more than 50 people, the inequality that models the number of students he can still recruit is:
[tex]s + j \leq 50[/tex]
In this problem:
- Already recruited 28 senior high students, hence [tex]s = 28[/tex].
- Already recruited 5 junior high students, want to recruit more, hence [tex]j = j + 5[/tex].
Then:
[tex]28 + j + 5 \leq 50[/tex]
[tex]33 + j \leq 50[/tex]
[tex]j \leq 17[/tex]
The maximum number of junior high school student he can still recruit is of 17.
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