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A community hall is in the shape of a cuboid.
The hall is 40m long, 15m wide and 3m high.
The community hall needs re-decorating, with new paint for the walls and the ceiling, and new tiles on the floor.
A 10L tin of paint covers 25m2 and costs £10.
1m2 floor tiles costs £3 each.

Work out the total cost of paint and tiles needed to re-decorate the community hall.

Sagot :

davimbarreto2007

Answer:

The total paint cost is £380. The total tiles cost is £1800. The total cost is £2180.

Step-by-step explanation:

To know the cost, you need to calculate the area of the community hall.

  • Area of the ceiling/floor: 40m x 15m =  600m2

So together, their area is 1200m2.

  • Area of the small walls of the community hall: 15m x 3m = 45m2/each wall

Together the two walls have an area of 90m2

  • Area of the big walls of the community hall: 40m x 3m = 120m

Together the two big walls have an area of 240m2

  • So, therefore, the total area of the community hall: 1530m2

Painting:

They are going to paint the walls and the ceiling and each 10L tin covers 25m2 so:

Area of the walls and ceiling = 600m2 + 90m2 + 240m2 = 930m2

930m2 ÷ 25m2 = 37.5 tins. Since you can't have half a tin, they will need 38 10L tins.

38 x £10 = £380

Floor:

1m2 floor tiles costs £3 so 600m2 x £3 = £1800

Total:

£1800 + £380 = £2180

Answer:

£2556

Step-by-step explanation:

One side wall

A=15x3

=45m^2

Two of the walls is 45x2 =90m^2

Another wall

A=15x40

=600m^2

There's is 2 walls + ceiling wall are the same. So, 600x3=1800m^2

Now add up what needs to be painted. So, 90m^2 +1800m^2 = 1890m^2.

We know:

10L :25m^2

1890m^2 ÷ 25m^2 = 75.6.

25 x75. 6 = 1890

Thus, 10 x 75.6 = 756L of paint needed.

10L : £10

756L : £x

From 10L to 756L, you multiply by 75.6 and you multiply this answer by £10 to get cost of £756

Floor is same shape as one of the walls, which is 600m^2 (40x15).

We know -

1m^2 : £3

So, we got 600m^2 and the cost of that will be 600 x £3 = £1800

£1800 + £756= £2556

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