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PLEASE HELP

For the following right triangle, find the side length x. Round your answer to the nearest hundredth.
8
Х
?
11


PLEASE HELP For The Following Right Triangle Find The Side Length X Round Your Answer To The Nearest Hundredth 8 Х 11 class=

Sagot :

Answer:

x = 13.60

Step-by-step explanation:

since it is a right angled triangle , we can use pythagoras theorem ,

hypotenuse^2 = base^2 + perpendicular^2

hypotenuse is the side opposite to the right angle .so here,

H = x .you can take base as 11 and perpendicular as 8

h^2 = p^2 + b^2

x^2 = 8^2 + 11^2

x^2 = 64 + 121

x = [tex]\sqrt{185[/tex]

x = 13.60

nomin7

Answer:

13.60

Step-by-step explanation:

use Pythagoras theorem

it is c²=a²+b²

c is hypotenus which is the longest side of a right angle triangle

--->now just put 8 on a and 11 on b

this gives us

c²= 8²+11²

c²= under the root 185

[tex] \sqrt{185 } [/tex]

c² = 13.60147051

nearest hundredth is 13.60

hope you understood :)

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