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Sagot :
Answer:
Step-by-step explanation:
∠XBC = 55°
XB = XC. So, ΔXBC is an isosceles triangle
∠XCB = ∠XBC
∠XCB = 55°
In ΔXBC,
∠BXC + ∠XBC + ∠XCB = 180 {Angle sum property of triangle}
∠BXC +55 +55 = 180
∠BXC + 110 = 180
∠BXC = 180 -110
∠BXC = 70°
Answer:
Given : XYAB
Solution:
(a) if XY || AB ad AB is the transversal line
then
<AXY = <XBC (Corresponding angles )
now
(b) since XB = XC XBC is the isosceles triangle
therefore
<XBC = <XCB (angle opposite to equal side are equal)
now , in triangle XBC
<XBC + <XCB + <BXC = 180° (angle sum property)
55 + 55 + <BXC = 180°
<BXC = 180°- 110° <BXC = 70°
hence ,<BXC = 70°
I hope this help u
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