Answered

Welcome to Westonci.ca, your go-to destination for finding answers to all your questions. Join our expert community today! Get immediate answers to your questions from a wide network of experienced professionals on our Q&A platform. Get immediate and reliable solutions to your questions from a community of experienced professionals on our platform.

A 900-kg car traveling east at 15. 0 m/s suddenly collides with a 750-kg car traveling north at 20. 0 m/s. The cars stick together after the collision. In what direction does the wreckage move just after the collision?.

Sagot :

LammettHash

By conservation of momentum,

(900 kg) (15.0 m/s) i + (750 kg) (20.0 m/s) j = (900 kg + 750 kg) v

where v is the velocity vector of the combined cars. Solve for v :

(13,500 i + 15,000 j) kg•m/s = (1650 kg) v

v ≈ (8.18 i + 9.09 j) m/s

Then the direction of v relative to East is θ such that

tan(θ) ≈ 9.09/8.18   ⇒   θ ≈ 48.0°

so the wreckages would move at approximately 48.0° north of east.

We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. We hope our answers were useful. Return anytime for more information and answers to any other questions you have. Thank you for visiting Westonci.ca, your go-to source for reliable answers. Come back soon for more expert insights.