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p^2 _ p^2 = 7 and p _ q = 2
find the value of p+q


Sagot :

Answer:

Hey There!

Let's solve...

[tex] {p}^{2} - {q}^{2} = ( p - q)(p + q) \\ \\ = 2(p + q) \\ \\ = \frac{7}{p + q} \\ \\ = \frac{7}{2} [/tex]

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Cheers!____________

The value of p+q is 7/2

Difference of two squares

Given the difference of two square

p^2 - q^2 = 7

Using the formula for finding the p+q

(p+q)(p-q) = 7

Given that p-q = 2

Substitute into the formula

2(p+q) = 7

p+q = 7/2

Hence the value of p+q is 7/2

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