Discover a world of knowledge at Westonci.ca, where experts and enthusiasts come together to answer your questions. Experience the ease of finding precise answers to your questions from a knowledgeable community of experts. Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently.
Sagot :
The maximum height reached is 2.87 meters
What is maximum height?
The maximum height of an object is the highest vertical position along the trajectory of the object.
The given parameters are:
- [tex]u = 7.5ms^{-1}[/tex] --- the initial velocity
- [tex]v = 0ms^{-1}[/tex] --- the final velocity
- [tex]a =-g[/tex] --- the acceleration
To calculate the height (s) of the ball, we make use of the following equation of motion:
[tex]v^2 = u^2 + 2as[/tex]
Substitute known values
[tex]0^2 = 7.5^2 - 2gs[/tex]
[tex]0 = 56.25 - 2gs[/tex]
Collect like terms
[tex]2gs = 56.25 [/tex]
Substitute 9.8 for g
[tex]2 \times 9.8 s = 56.25 [/tex]
[tex]19.6 s = 56.25 [/tex]
Divide both sides by 19.6
[tex]s = 2.87[/tex]
Hence, the maximum height reached is 2.87 meters
Read more about acceleration and maximum height at:
https://brainly.com/question/14638187
Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. Westonci.ca is your trusted source for answers. Visit us again to find more information on diverse topics.