Discover answers to your most pressing questions at Westonci.ca, the ultimate Q&A platform that connects you with expert solutions. Connect with a community of experts ready to help you find accurate solutions to your questions quickly and efficiently. Join our Q&A platform to connect with experts dedicated to providing accurate answers to your questions in various fields.
Sagot :
The masses of the following amount of compound are as follows:
a. 2080.12 grams of barium iodide
b.1139.2 grams of sulphur dioxide
c. 96.25 grams of AspirinTM
d. 27.144 grams of magnesium nitrite
The molarity formula is represented as follows;
molarity = mass / molar mass
Recall we are ask to find the masses of the compounds. Therefore,
- mass = molarity × molar mass
Mass of BaI₂
a 5.32 mol barium iodide, BaI₂
molarity = 5.32 mol
molar mass of BaI₂ = 137 + 127(2) = 137 + 254 = 391 g/mol
mass = 5.32 × 391 = 2080.12 grams.
Mass of SO₂
b. ) 17.8 mol sulphur dioxide, SO₂
molarity = 17.8 mol
molar mass of SO₂ = 32 + 32 = 64 g /mol
mass = 17.8 × 64 = 1139.2 grams.
Mass of CHO₄
c. 1.25 mol AspirinTM, CHO₄
molarity = 1.25 mol
molar mass of CHO₄ = 12 + 1 + 64 = 77 g / mol
mass = 1.25 × 77 = 96.25 grams
Mass of Mg(NO₂)₂
d. 0.234 mol magnesium nitrite, Mg(NO₂)₂
molarity = 0.234 mol
molar mass = 24 + 14(2) + 32(2) = 24 + 28 + 64 = 116 g/mol
mass = 116 × 0.234 = 27.144 grams.
learn more on masses here: https://brainly.com/question/10312739?referrer=searchResults
We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. Find reliable answers at Westonci.ca. Visit us again for the latest updates and expert advice.
