Answered

Westonci.ca offers quick and accurate answers to your questions. Join our community and get the insights you need today. Our platform offers a seamless experience for finding reliable answers from a network of knowledgeable professionals. Our platform provides a seamless experience for finding reliable answers from a network of experienced professionals.

An ice skating competition features 8 skaters. How many different ways can the skaters finish the competition? how many different ways can 3 of the skaters finish first, second and third?.

Sagot :

abidemiokin

The number of ways the skaters can finish the competition is 40,320 ways

The different ways 3 of the skaters finish first, second and third is 56 ways

Given the following

  • Number of skaters featured = 8 skaters

If the skaters finish the competition, the number of different ways the skaters finish the competition is expressed as:

8! = 8*7*6*5*4*3*2

8! = 56*30*24

8! = 40,320.

The number of ways the skaters can finish the competition is 40,320 ways

If 3 of the skaters finish first, second and third, the number of ways this can be done is given as:

8C3 = 8!/(8-3)!3!

8C3 = 8!/5!3!

8C3 = 8*7*6*5!/5!3!

8C3 = 56 ways

Hence the different ways 3 of the skaters finish first, second and third is 56 ways

Learn more on combination here: https://brainly.com/question/11732255

Thank you for choosing our service. We're dedicated to providing the best answers for all your questions. Visit us again. Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. Keep exploring Westonci.ca for more insightful answers to your questions. We're here to help.