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An ice skating competition features 8 skaters. How many different ways can the skaters finish the competition? how many different ways can 3 of the skaters finish first, second and third?.

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abidemiokin

The number of ways the skaters can finish the competition is 40,320 ways

The different ways 3 of the skaters finish first, second and third is 56 ways

Given the following

  • Number of skaters featured = 8 skaters

If the skaters finish the competition, the number of different ways the skaters finish the competition is expressed as:

8! = 8*7*6*5*4*3*2

8! = 56*30*24

8! = 40,320.

The number of ways the skaters can finish the competition is 40,320 ways

If 3 of the skaters finish first, second and third, the number of ways this can be done is given as:

8C3 = 8!/(8-3)!3!

8C3 = 8!/5!3!

8C3 = 8*7*6*5!/5!3!

8C3 = 56 ways

Hence the different ways 3 of the skaters finish first, second and third is 56 ways

Learn more on combination here: https://brainly.com/question/11732255

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