marcuscheeatow
Answered

At Westonci.ca, we connect you with the answers you need, thanks to our active and informed community. Discover reliable solutions to your questions from a wide network of experts on our comprehensive Q&A platform. Connect with a community of professionals ready to provide precise solutions to your questions quickly and accurately.

What is an equation of the line that passes through the points (1, 2)(1,2) and (2, -1)(2,−1)?

Sagot :

abiafalak8

Answer:

y = -3x + 4

Step-by-step explanation:

First, we find the slope, and to find the slope;[tex]\frac{y_{2} - y_{1}}{x_{2} - x_{1} }[/tex]

Slope : -3

Now we fill in the equation with a point and find the y- intercept:

2 = -3(1) + b

2 = -2 + b

4 = b

y = -3x + 4

SpiritInly

Answer:

[tex]y = - 3x + 5[/tex]

Step-by-step explanation:

to find the gradient/slope between these points:

[tex]\frac{y_{2} - y_{1}}{x_{2} - x_{1} } [/tex]

[tex] \frac{ - 1 -2}{2 - 1} = - 3[/tex]

the gradient is -3

we need to write the equation in the form y=mx+c. Choose any of the two coordinates in the question. I'll choose (1,2).

y is 2, x is 1 and m is the gradient which is -3

working out c:

[tex]y = mx + c[/tex]

[tex]2 = - 3(1) + c[/tex]

[tex]2 = - 3 + c[/tex]

add 3 on both sides

[tex]2 + 3 = c[/tex]

[tex]c = 5[/tex]

final equation:

[tex]y - = - 3x + 5[/tex]

Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. We're here to help at Westonci.ca. Keep visiting for the best answers to your questions.