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Given that f(x) = 2x + 1 and g(x) = the quantity of 3x minus 1, divided by 2 , solve for g(f(3)).

Sagot :

itsandypandy

Answer:

10

Step-by-step explanation:

Firstly, find the value of f(3)

⇒ [tex]f(3) = 2(3) + 1[/tex]   [sub in 3]

⇒ [tex]f(3) = 7[/tex]   [multiply by 2 and add 1]

Now, find g(f(3))

⇒ [tex]g(f(3)) = \frac{3(7) - 1}{2}[/tex]   [sub in 7]

⇒ [tex]g(f(3)) = \frac{20}{2}[/tex]   [multiply by 3 and subtract 1]

⇒ [tex]g(f(3)) = 10[/tex]   [divide by 2]

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