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Sagot :

The equation of a circle is the equation that represents the circle on the coordinate plane

The equation of the circle is [tex](x +3)^2 + (y -6)^2 = 13[/tex]'

From the attached figure, we have the following parameters:

  • Center: (a,b) = (-3, 6)
  • Point on the circumference: (x,y) = (0,8)

Start by calculating the radius r using the following distance formula

[tex]d = \sqrt{(x -a)^2 +(y - b)^2}[/tex]

So, we have:

[tex]r = \sqrt{(0 --3)^2 +(8 - 6)^2}[/tex]

[tex]r = \sqrt{9 +4}[/tex]

[tex]r = \sqrt{13}[/tex]

Square both sides

[tex]r^2 = 13[/tex]

The equation of the circle is then calculated as:

[tex](x - a)^2 + (y -b)^2 = r^2[/tex]

Substitute values for a and b

[tex](x - -3)^2 + (y -6)^2 = r^2[/tex]

This gives

[tex](x +3)^2 + (y -6)^2 = r^2[/tex]

Substitute [tex]r^2 = 13[/tex]

[tex](x +3)^2 + (y -6)^2 = 13[/tex]

Hence, the equation of the circle is [tex](x +3)^2 + (y -6)^2 = 13[/tex]'

Read more about circle equations at:

https://brainly.com/question/1559324