Using a system of equations, it is found that the meter contains 20 dimes and 10 quarters.
System of equations:
For the system, the variables are:
- x is the number of dimes.
- y is the number of quarters.
A dime is worth $0.1 and a quarter is worth $0.25. In total, the parking meter is filled with $4.50, hence:
[tex]0.1x + 0.25y = 4.5[/tex]
There are twice as many dimes as quarters, hence:
[tex]x = 2y[/tex]
Then:
[tex]0.1x + 0.25y = 4.5[/tex]
[tex]0.1(2y) + 0.25y = 4.5[/tex]
[tex]0.2y + 0.25y = 4.5[/tex]
[tex]0.45y = 4.5[/tex]
[tex]y = \frac{4.5}{0.45}[/tex]
[tex]y = 10[/tex]
[tex]x = 2y = 2(10) = 20[/tex]
There are 20 dimes and 10 quarters in the parking meter.
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