Answered

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A parking meter filled with \$4.50$4.50 in dimes and quarters contains twice as many dimes as quarters.(Note: 1 dime = \$.10$.10; 1 quarter = \$.25$.25)

Sagot :

Using a system of equations, it is found that the meter contains 20 dimes and 10 quarters.

System of equations:

For the system, the variables are:

  • x is the number of dimes.
  • y is the number of quarters.

A dime is worth $0.1 and a quarter is worth $0.25. In total, the parking meter is filled with $4.50, hence:

[tex]0.1x + 0.25y = 4.5[/tex]

There are twice as many dimes as quarters, hence:

[tex]x = 2y[/tex]

Then:

[tex]0.1x + 0.25y = 4.5[/tex]

[tex]0.1(2y) + 0.25y = 4.5[/tex]

[tex]0.2y + 0.25y = 4.5[/tex]

[tex]0.45y = 4.5[/tex]

[tex]y = \frac{4.5}{0.45}[/tex]

[tex]y = 10[/tex]

[tex]x = 2y = 2(10) = 20[/tex]

There are 20 dimes and 10 quarters in the parking meter.

To learn more about system of equations, you can take a look at https://brainly.com/question/24342899

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