Answer:
1.jayant is 18 and jana is 12
2.30,31
Step-by-step explanation:
1.let jana be x
so jayant is x+6( Jayant is 6 years older than Jaya)
x+(x+6)=30
or,2x+6=30
or,2x=30-6
or,x=24/2
or,x=12
jaya=12
jayant=x+6=12+6=18
2.
given,
The sun of two consecutive numbers
so,let 1 be x and another be x+1
x+(x+1)=61
or,2x=61-1
or,x=60/2
or,x=30
x+1=31
Answer:
Jaya is 12, Jayant is 18
The consecutive numbers are 30 and 31.
Step-by-step explanation:
Let x = Jaya's age
Let x+6 = Jayant's age
We put the plus 6 on there bc Jayant is 6 years older.
The sum of their ages is 30 (sum means adding) So we write that as
x + x + 6 = 30
Combine like terms (the two x's)
2x + 6 = 30
Subtract 6 from both sides.
2x = 24
Divide both sides by 2
x = 12
So Jaya is 12 and Jayant is 18. That makes Jayant 6 years older and their ages together 30.
Secondly, consecutive number means two numbers right in a row. So one number will be n and the next number is n+1.
Their sum (again, adding) is 61. So,
n + n + 1 = 61
2n + 1 = 61
2n = 60
n = 30
So one number is 30 and the next is 31. They are consecutive numbers and their sum is, in fact, 61.
