Answered

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Traffic flow at 1st Ave and High St is twice the traffic flow at 2nd ave and central. Compare the graph of the traffic flow at 1st Ave and High St to the graph of the traffic flow at 2nd Ave and Central over time

Sagot :

lauraleiiscool

Answer:

The period of the graph of the traffic flow at 1st Ave and High St is half as long as the period of the graph of the traffic flow at 2nd Ave and Central.

Step-by-step explanation:

Parrain

The correct comparison is that the period of the graph showing the traffic at 1st Ave and High St will be half the length of the graph for 2nd ave and central.

How do the graphs compare?

The periods of the two graphs will be different because of the difference in traffic flow.

As a result of the traffic flow in 1st Ave being twice the flow in 2nd Ave, 1st Ave. will have half the period because a period shows the length of a graph's cycle. Higher traffic equals lower period.

Find out more on graph period at https://brainly.com/question/3511043.

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