Answered

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PLEASE HELP ME I DONT UNDERSTAND THIS AND THIS IS TIMED
In an experiment, a rubber stopper is attached to one end of a string. The stopper is whirled in a horizontal circular path of a diameter of 1.0 meter at a constant speed. The stopper completes one revolution in 0.2 seconds. Approximately what is the magnitude of the stoppers speed?

A) 3.1 m/s
B) 6.3 m/s
C) 16 m/s
D) 31 m/s

Sagot :

Trancescient

(C)

Explanation:

The circle has a radius r = 0.5 m, which means that its circumference C is

[tex]C = 2\pi r = 2\pi(0.5\:\text{m}) = 3.14\:\text{m}[/tex]

One revolution means that the stopper travels a distance equal to the circumference of the circle so the velocity of the stopper is

[tex]v = \dfrac{C}{t} =\dfrac{3.14\:\text{m}}{0.2\:\text{s}} = 15.7\:\text{m/s} \approx 16\:\text{m/s}[/tex]

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