Answered

Explore Westonci.ca, the top Q&A platform where your questions are answered by professionals and enthusiasts alike. Connect with a community of experts ready to help you find accurate solutions to your questions quickly and efficiently. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.

A pole vaulter rested a 17 foot pole against a wall. If the top of the pole hit the wall 14 feet above the ground, how far from the wall is the bottom of the pole

Sagot :

chetankachana

Answer:

a = √93

a ≈ 9.64

Step-by-step explanation:

We can use the Pythagorean theorem for this: a² + b² = c²

c is given as the hypotenuse, which is the pole with a length of 17 ft

c² is 17²

b is a leg with a height of 14 ft

b² = 14²

We need to find the base leg, a,  distance from the wall to the base of the pole.

Solve:

a² + 14² = 17²

a² + 196 = 289

a² = 93

a = √93

-Chetan K

Thanks for using our platform. We're always here to provide accurate and up-to-date answers to all your queries. Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. We're here to help at Westonci.ca. Keep visiting for the best answers to your questions.