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find the volume of hydrogen (at STP) necessary to saturate 7.8 grams of benzene? ( C:12, H:1) n=m/M, V=n*STP, STP:22.4L/mol​

Sagot :

Considering the definition of molar mass and STP conditions, 7.8 grams of benzene will ocupy at STP 2.24 L.

Molar mass

Molar mass is the amount of mass that a substance contains in one mole.

In the periodic table, you can find the molar mass of the elements, also called atomic mass or atomic weight.

To calculate the molecular mass of a compound, also called mass or molecular weight, the molar mass of the elements of the compound must be added multiplied by the times they appear.

STP conditions

The STP conditions refer to the standard temperature and pressure. Pressure values at 1 atmosphere and temperature at 0 ° C are used and are reference values for gases. And in these conditions 1 mole of any gas occupies an approximate volume of 22.4 liters.

This case

Benzene is an aromatic hydrocarbon with the molecular formula C₆H₆. So, being the molar mass of the elements C 12 g/mole and H 1 g/mole, the molecular mass can be calculated as:

C₆H₆: 6×12 g/mole + 6×1 g/mole

C₆H₆: 78 g/mole

Then, you can apply the following rule of three: if 78 grams of the compound are contained in 1 mole, 7.8 grams are contained in how many moles?

[tex]number of moles=\frac{7.8 gramsx1 mole}{78 grams}[/tex]

number of moles= 0.1 moles

Now, you can apply the following rule of three, taking into account the definition of STP conditions: if by definition of STP conditions 1 mole of O₂ occupies a volume of 22.4 liters, 0.1 moles occupies how much volume?

[tex]volume=\frac{0.1 molex22.4 L}{1 mole}[/tex]

volume= 2.24 L

Finally, 7.8 grams of benzene will ocupy at STP 2.24 L.

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