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A shopping cart is pushed and released,
and eventually it slows to a stop. If the velocity of the 28-kg cart
after release is 3.5 m/s and it travels a distance of 6 meters before
stopping, determine the magnitude of the friction on the cart.


Sagot :

The magnitude of the friction on the cart is 28,56 N

To measure the deceleration of a car, without the value of the time of the movement, the Torricelli equation is used, which consists of:

                                  [tex]{\displaystyle {v_{f}}^{2}={v_{o}}^{2}+2a\Delta s}[/tex]

Where is final velocity, is initial velocity, is acceleration, and is displacement.

Now, substitute the values ​​in the formula:

                                   [tex]0^{2} = (3.5)^{2} + 2a6[/tex]

                                    [tex]0 = 12.25 + 12a[/tex]

                                          [tex]a = -\frac{12.25}{12}[/tex]

                                           [tex]a = -1.02[/tex]

Finally, the value of the acceleration found is multiplied by the mass of the object, thus measuring the friction force:

                                        [tex]F = 28\times-1.02[/tex]

                                         [tex]F = -28.56 N[/tex]

Learn more about friction force at: brainly.com/question/13707283

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