Answered

Find the information you're looking for at Westonci.ca, the trusted Q&A platform with a community of knowledgeable experts. Discover solutions to your questions from experienced professionals across multiple fields on our comprehensive Q&A platform. Get precise and detailed answers to your questions from a knowledgeable community of experts on our Q&A platform.

Protein 1

black forest ham

70


Protein 2

chicken patty

80

Protein 3

oven-roasted turkey

60


Protein 4

steak

110


Protein 5

tuna

250



Your first client is a twenty-year-old female who has a lunch limit of 680 calories. Based on her topping choices, she already has amassed 125 calories.


Construct and solve an inequality to determine the possible number of servings of one protein of your choice (refer to the table in part a) she can eat and stay under her limit.

Sagot :

adioabiola

The inequality to determine the possible number of servings of one protein (Protein 1) she can eat and stay under her limit is; 70P1 <= 555 and the solution is; P1 <= 7.93.

Since, the client has a lunch limit of 680 calories and has already amassed 125 calories.

In essence, the amount of protein which she can take to remain within her calories tolerance level can be evaluated as follows;

  • Protein <= 680 - 125

  • Protein <= 555.

By choosing Protein 1: Black forest ham which supplies 70 calories for each taken; We have;

  • 70P1 <= 555

  • P1 <= 555/70

  • P1 <= 7.93.

Ultimately, the inequality to determine the possible number of servings of one protein (Protein 1) she can eat and stay under her limit is; 70P1 <= 555 and the solution is; P1 <= 7.93.

Read more on inequalities:

https://brainly.com/question/14361489

We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. We hope our answers were useful. Return anytime for more information and answers to any other questions you have. We're here to help at Westonci.ca. Keep visiting for the best answers to your questions.