Explore Westonci.ca, the leading Q&A site where experts provide accurate and helpful answers to all your questions. Get quick and reliable solutions to your questions from a community of experienced experts on our platform. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.
Sagot :
The specific heat capacity of this chunk of metal is equal to 0.32 J/g°C.
Given the following data:
- Mass of metal = 250g
- Quantity of energy = 400 Joules
- Initial temperature = 20°C
- Final temperature = 20°C
To determine the specific heat capacity of this chunk of metal:
The formula for quantity of heat.
Mathematically, quantity of heat is given by the formula;
[tex]Q = mc\theta[/tex]
Where:
- Q represents the quantity of heat.
- m represents the mass of an object.
- c represents the specific heat capacity.
- ∅ represents the change in temperature.
Making c the subject of formula, we have:
[tex]c = \frac{Q}{m\theta}[/tex]
Substituting the given parameters into the formula, we have;
[tex]c = \frac{400}{250 \times (25-20)}\\\\c = \frac{400}{250 \times 5}\\\\c = \frac{400}{1250 }[/tex]
Specific heat, c = 0.32 J/g°C.
Read more on specific heat here: https://brainly.com/question/2834175
Visit us again for up-to-date and reliable answers. We're always ready to assist you with your informational needs. Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. Westonci.ca is here to provide the answers you seek. Return often for more expert solutions.