At Westonci.ca, we connect you with experts who provide detailed answers to your most pressing questions. Start exploring now! Experience the ease of finding accurate answers to your questions from a knowledgeable community of professionals. Join our Q&A platform to connect with experts dedicated to providing accurate answers to your questions in various fields.

A trolley of mass 3 kg moves at a velocity of 8ms-1. trolley B of mass 4kg follows behind trolley A in the same direction at a velocity of 9ms-1 catches up with A and collides with it. after collision trolley A still moves in the same direction but now at a velocity of 9ms-1. calculate the velocity of trolley B after collision

Sagot :

Let v be the velocity of trolley B after collision. Then by conservation of momentum,

(3 kg) (8 m/s) + (4 kg) (9 m/s) = (3 kg) (9 m/s) + (4 kg) v

Solve for v :

24 kg•m/s + 36 kg•m/s = 27 kg•m/s + (4 kg) v

33 kg•m/s = (4 kg) v

v = (33 kg•m/s) / (4 kg) = 8.25 m/s

Thank you for trusting us with your questions. We're here to help you find accurate answers quickly and efficiently. We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. We're here to help at Westonci.ca. Keep visiting for the best answers to your questions.