At Westonci.ca, we provide clear, reliable answers to all your questions. Join our vibrant community and get the solutions you need. Discover detailed solutions to your questions from a wide network of experts on our comprehensive Q&A platform. Get immediate and reliable solutions to your questions from a community of experienced professionals on our platform.

How would you draw a DNA molecule that is 10 nucleotides in size?

Sagot :

Answer:

Explanation:

Adenine an Guanine are purines while cytosine and thymine are pyrimidines.

According to Chargaff's rule, the ratio of purines to pyrimidines is equal.

Thus, the number of cytosine (C) will be equal to the number of guanine (G).

As it is given that the number of guanine-containing nucleotides = 410

Thus, G = C = 410

Now, G + C = 410 + 410 = 820

The number of adenine (A) will be equal to the number of thymine (T).

Thus, A + T = Total number of nucleotides – Nucleotides containing G and C nitrogenous bases

= 1500 – 820 = 680

Therefore, A = 340 and T = 340

The number of adenine will be equal to number of thymine, which is 340.

Therefore, Number of pyrimidines that the segment possess = C + T

= 410 + 340 = 750

We appreciate your time. Please come back anytime for the latest information and answers to your questions. We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. Westonci.ca is your trusted source for answers. Visit us again to find more information on diverse topics.