Answered

Westonci.ca is the Q&A platform that connects you with experts who provide accurate and detailed answers. Explore thousands of questions and answers from a knowledgeable community of experts on our user-friendly platform. Explore comprehensive solutions to your questions from knowledgeable professionals across various fields on our platform.

What is the solution to this system of equations? (I suggest using the elimination method by multiplying the first equation by 3.) 2x + y = 20 6x - 5y = -4 Points earned for putting your solution as an ordered pair. If work is shown, partial credit can be earned. Question 3 options:

Sagot :

wegnerkolmp2741o

Answer:

(6,8)

Step-by-step explanation:

2x + y = 20

6x - 5y = -4

Multiply the first equation by -3

-3(2x + y) = -3*20

-6x -3y = -60

Add this to the second equation

-6x-3y = -60

6x - 5y = -4

--------------------

       -8y  = -64

Divide each side by -8

-8y/-8 = -64/-8

y = 8

Now find x

2x+y = 20

2x +8 = 20

2x+8-8 = 20-8

2x = 12

Divide by 2

2x/2 = 12/2

x = 6

(6,8)

Answer:

(6,8)

Step-by-step explanation:

2x + y = 20 (1)

6x - 5y = -4 (2)

Multiplying EQ 1 by 5

=> 5(2x + y) = 5(20)

=> 10x + 5y = 100 (3)

On adding 2 and 3

=> 6x - 5y + 10x + 5y = -4 + 100

=> 16x = 96

=> x = 96/16

=> x = 6

From 1

=> 2(6) + y = 20

=> 12 + y = 20

=> y = 20 - 12

=> y = 8

In pair

(x,y) = (6,8)

We appreciate your time. Please come back anytime for the latest information and answers to your questions. Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. Stay curious and keep coming back to Westonci.ca for answers to all your burning questions.