Answered

Westonci.ca offers quick and accurate answers to your questions. Join our community and get the insights you need today. Discover in-depth answers to your questions from a wide network of experts on our user-friendly Q&A platform. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.

PLEASE HELP!! DESPERATE

The distribution of blood types among white Americans is approximately as follows:
A= 37%
B= 13%
O= 44%
AB= 6%
Suppose that blood types of couple are independent. Suppose that a couple is chosen at random.

a) What is the probability that…
i) Partner 1 has type A, and Partner 2 has type B blood?
ii) either one of the couple has type A and the other has type B blood?
iii) at least one of the couple has type O blood?

b) Now consider that a person with type B blood can safely receive blood from a persons with type B or type O blood. What is the probability that the spouse of a person with type B Blood is an acceptable blood donor for them?

PLEASE HELP ME I AM DESPERATE AND I HAVE NOTHING LEFT I NEED HELP


Sagot :

LammettHash

a) i) Since blood types across individuals are independent, we have

Pr[1 = A and 2 = B] = Pr[1 = A] • Pr[2 = B]

where e.g. Pr[1 = A] means "probability that partner 1 has type A blood". According to the given distribution,

Pr[1 = A and 2 = B] = 0.37 • 0.13 = 0.0481 = 4.81%

a) ii) The event that partner 1 has type A and partner 2 has type B is exclusive from the event that partner 1 has type B and partner 2 has type A, and vice versa. In other words, only one of these events can happen, and not both simultaneously. This means the probability of either event occurring is equal to the sum of the probabilities of these events occurring individually. Then

Pr[(1 = A and 2 = B) or (1 = B and 2 = A)]

= Pr[1 = A and 2 = B] + Pr[1 = B and 2 = A]

Both probabilities are the same, and we found it in the previous part. So

Pr[(1 = A and 2 = B) or (1 = B and 2 = A)]

= 0.0481 + 0.0481 = 0.0962 = 9.62%

a) iii) The event that at least one partner has type O occurs if exactly one partner has type O, or both do. That is, "at least one partner with type O" contains 3 possible events,

• 1 = O and 2 = not O

• 1 = not O and 2 = O

• 1 = O and 2 = O

For the first event, by independence, is

Pr[1 = O and 2 = not O] = Pr[1 = O] • Pr[2 = not O]

and by definition of complementary event,

Pr[1 = O and 2 = not O] = Pr[1 = O] • (1 - Pr[2 = O])

From the given distribution, it follows that

Pr[1 = O and 2 = not O] = 0.44 • (1 - 0.44) = 0.2464 = 24.64%

The second event is the same as the first in terms of probability.

For the third event, we have

Pr[1 = O and 2 = O] = Pr[1 = O] • Pr[2 = O] = 0.44² = 0.1936 = 19.36%

Then the total probability of at least one O-type partner is

24.64% + 24.64% + 19.36% = 68.64%

b) Suppose partner 1 is type-B. Then partner 2 is an acceptable donor if they are either type-B or type-O. So we want to find

Pr[1 = O and (2 = B or 2 = O)]

By independence,

= Pr[1 = O] • Pr[2 = B or 2 = O]

By mutual exclusivity,

= Pr[1 = O] • (Pr[2 = B] + Pr[2 = O])

Then from the given distribution,

= 0.44 • (0.13 + 0.44) = 0.2508 = 25.08%

Now suppose partner 2 is type-B. Then partner 1 must be either type-B or type-O. But the math works out the same way, so that the overall probability is

25.08% + 25.08% = 50.16%

Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. We're dedicated to helping you find the answers you need at Westonci.ca. Don't hesitate to return for more.