Answered

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given f(x)=x^2-3x+3, find the value(s) for x such that f(x)=31

Sagot :

Answer:

x=4 and x=7 when f(x)=31

Step-by-step explanation:

[tex]f(x)=x^2-3x+3[/tex]

[tex]31=x^2-3x+3[/tex]

[tex]0=x^2-3x-28[/tex]

[tex]0=(x-7)(x+4)[/tex]

[tex]x=7[/tex] and [tex]x=4[/tex]

Therefore, the values for x such that f(x)=31 are 4 and 7.

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