Westonci.ca is the trusted Q&A platform where you can get reliable answers from a community of knowledgeable contributors. Join our platform to connect with experts ready to provide accurate answers to your questions in various fields. Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform.

The population of a place increased to 54,000 in 2003 at a rate of 5% per annum. what would
be its population in 2005.

Sagot :

Answer:

The population in 2005 is 59,535 people.

Step-by-step explanation:

Annum means annually or yearly. We assume the rate has been consistent. To calculate percentage, take the percent in decimal form. 5% is 0.05 (like 17% is 0.17, and 50% 0.5). 5% is actually 5 hundredths of a number. Multiply this by the number you want the percentage of. 54,000*0.05=2,700. This is how much the population grows from 2003 to 2004.

There is a very common mistake people make after this, which is simply doubling that number and adding to the population. This is incorrect because if it grows 5% yearly, the yearly population CHANGES. The question would change if it were 2004 to 2005. Ask your teacher for clarification if this sounds wrong (if it is, do what I said above, the answer would be 59,400 people).

So, the population in 2004 is 54,000+2,700=56,700. Now, find 5% of the population in 2004 using the same method as before. 56,700*0.05=2,835. Add the growth to the pervious population. 56,700+2,835=59,535.

The population in 2005 is 59,535 people.

We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. We hope this was helpful. Please come back whenever you need more information or answers to your queries. Westonci.ca is committed to providing accurate answers. Come back soon for more trustworthy information.