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If principal = ₹100000, rate of interest = 10% compounded half-yearly. Find
i. Interest for 6 months.
ii. Amount after 6 months.
iii. Interest for the next 6 months.
iv. Amount after one year.

Sagot :

Answer:

i. ₹5000

ii. ₹105000

iii. ₹5250

iv. ₹110250

Step-by-step explanation:

[tex]X\ represents\ the\ times\ symbol.[/tex]

i.

[tex]100000\ X (\frac{10}{100\ X\ 2})^{1} \ \ for\ 6\ months\\= 5000[/tex]

ii.

[tex]100000+5000=105000[/tex]

iii.

[tex]100000\ X (1+\frac{10}{100\ X\ 2})^{2} \ \ for\ 12\ months\\= 110250\\\\110250-100000-5000=5250[/tex]

iv.

[tex]110250[/tex]

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