Looking for reliable answers? Westonci.ca is the ultimate Q&A platform where experts share their knowledge on various topics. Our platform offers a seamless experience for finding reliable answers from a network of experienced professionals. Experience the ease of finding precise answers to your questions from a knowledgeable community of experts.

Find the equation of the directrix of the parabola found in part A.

Find The Equation Of The Directrix Of The Parabola Found In Part A class=

Sagot :

The specific equation of the parabola can be found by plugging the given

values of the variables of the general equation.

Correct Response;

  • [tex]\displaystyle The \ equation \ of \ the \ parabolic \ reflector \ is; \ \underline{ y = \frac{1}{12} \cdot x^2}[/tex]

Method used to obtain the above equation;

Given parameters;

The vertex of the parabola is at the origin with coordinates (0, 0)

The location of the focus = 3 cm from the vertex

Required:

The equation that models the parabola.

Solution:

The vertex form of the equation of a parabola is y = a·(x - h)² + k

The above equation can be expressed as (x - h)² = 4·p·(y - k)

Where in a vertical parabola;

(h + p, k) = The coordinates of the focus

(h, k) = The coordinates of the vertex = (0, 0)

p = 3 = The distance of the focus from the vertex

Therefore, the coordinates of the focus = (0 + 3, 0) = (3, 0)

The equation of the parabola is therefore;

(x - 0)² = 4×3 × (y - 0) = 12·y

x² = 12·y

  • [tex]\displaystyle The \ equation \ of \ the \ parabola \ that \ models \ the \ reflector \ is; \ \underline{ y = \frac{1}{12} \cdot x^2}[/tex]

Learn more about the equation of a parabola here:

https://brainly.com/question/2131669

We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. Westonci.ca is your go-to source for reliable answers. Return soon for more expert insights.