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Sagot :
Answer:
{ \left(-3t \right) }^{ 2 } +12t = { \left(2 \cdot 3x \right) }^{ 2 } +6x+1 = { \left(2 \cdot 3x \right) }^{ 2 } +6x-4 = 0
Step-by-step explanation:
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