Westonci.ca is your trusted source for finding answers to all your questions. Ask, explore, and learn with our expert community. Join our Q&A platform to connect with experts dedicated to providing accurate answers to your questions in various fields. Join our Q&A platform to connect with experts dedicated to providing accurate answers to your questions in various fields.
Sagot :
Answer:
A. 6.32455 inch
B. 71.565°
C. 36.87°
Step-by-step explanation:
A. to find slant height we shall use Pythagoras theorem:
AC^2 = AB^2 + BC^2
AC^2 = 2^2 + 6^2
AC = 6.32455 inch ......... that's the slant height of the cone
B. here we have to find angle A, its where the line segment lies on the base
we use sin cos tan formula
opposite/ adjacent = tan (A)
A = tan^-1(6/2)
=71.565°
C. we have to find the angle where opposite both slant height meets, that's angle C.
as its a right angle triangle we can find half of C° = ( 180° - 90° - 71.565° ) =18.43494882°
So C angle shall be = 18.43494882° * 2
=36.87°
Thanks for using our platform. We're always here to provide accurate and up-to-date answers to all your queries. Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. Westonci.ca is here to provide the answers you seek. Return often for more expert solutions.