Answered

Welcome to Westonci.ca, where finding answers to your questions is made simple by our community of experts. Experience the ease of finding precise answers to your questions from a knowledgeable community of experts. Get precise and detailed answers to your questions from a knowledgeable community of experts on our Q&A platform.

A skydiver drops himself from a plane, he passes 100 m before opening a parachute. if he experiences free fall motion, how much is his final speed at that point?

Sagot :

Eduard22sly

The final speed of the skydiver at the point is 44.3 m/s

Determination of the time

We'll begin by calculating the time required to fall 100 m

  • Height (h) = 100 m
  • Acceleration due to gravity (g) = 9.8 m/s²
  • Time (t) =?

H = ½gt²

100 = ½ × 9.8 × t²

100 = 4.9 × t²

Divide both side by 4.9

t² = 100 / 4.9

Take the square root of both side

t = √(100 / 4.9)

t = 4.52 s

Determination of the velocity

Finally, we shall determine the velocity.

  • Time (t) = 4.52 s
  • Acceleration due to gravity (g) = 9.8 m/s²
  • Velocity (v) =?

v = gt

v = 9.8 × 4.52

v = 44.3 m/s

Learn more about motion under gravity:

https://brainly.com/question/2386393

daniloekn

Answer:

      I did this in school v^2 = u^2 + 2gh

v = final velocity

u = initial velocity

g = acceleration due to gravity

h = height

Since he dropped from a height, u = 0 m/s

v^2 = 0^2 + 2 (10) (100)

v^2 = 2000

v = √2000

v = 44.7 m/s

Explanation:

We hope our answers were helpful. Return anytime for more information and answers to any other questions you may have. Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. Get the answers you need at Westonci.ca. Stay informed by returning for our latest expert advice.