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- Saint Pauls Mid
Question 9
1 pts
Russ compared the heights of the players on two basketball teams, Team 1 and Team
2. He recorded the data as shown below.
HEIGHTS OF TWO TEAMS
Team 1
Tons
erary
Team 2
ul
60
65
70
75
80
| K-12
Heights (in inches)
Which statement best compares the medians and interquartile ranges of the two
teams?

Sagot :

It should be noted that the median is the middle number in a sorted form whether ascending or descending while the interquartile range tells one the spread of the middle half of the distribution.

Solving median and interquartile range.

Your information is incomplete. Therefore, an overview will be given. To find the median, arrange the numbers given in an ascending or descending order and the middle number is the median.

Also, you can count how many numbers you've. If you have an odd number, divide the numbers by 2 and then round up in order to get the position of the median. In a case where it's an even number, divide it by 2 and go the number in the position and average it with the number that's in the next higher position in order to get the median.

In order to find the interquartile range, let's assume that the given numbers are 48, 52, 57, 64, 72, 76, 77, 81, 85, and 88. We've then numbers and this can be grouped into 5 each.

The first 5 will be 48, 52, 57, 64, and 72. In this case, the median in the first half which is Q1 is 57. The second 5 will be 76, 77, 81, 85, and 88. The median in the second half which is Q2 is 81. Therefore, the interquartile range will be:

= Q3 - Q1

= 81 - 57

= 24

Learn more about median and interquartile range on:

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