Looking for trustworthy answers? Westonci.ca is the ultimate Q&A platform where experts share their knowledge on various topics. Get quick and reliable answers to your questions from a dedicated community of professionals on our platform. Explore comprehensive solutions to your questions from knowledgeable professionals across various fields on our platform.

Please help with this I’m so confused the teacher just threw this on us and called it a day lol

Please Help With This Im So Confused The Teacher Just Threw This On Us And Called It A Day Lol class=

Sagot :

Answer:

2A : 2.94 inches

2B : 2.718 in²

Step-by-step explanation:

We are given the formula

Highest Ultimate load = max compressive strength x cross sectional area

I think there is a typo in the equations here because the above equation was repeated twice, i'm guessing the second equation should be:

Highest Ultimate load = max tensile strength x cross sectional area

Problem 2A:

Given:

Highest Ultimate load = 135,900 lb

max compressive strength (concrete) = 5,000 lbs/in²

cross sectional area = π r² ; where r is the radius of the circle in inches

simply substitute the above into the first formula and solve for r:

Highest Ultimate load = max compressive strength x cross sectional area

135,900 = 5,000 x π r²

π r² = 135900 / 5000

π r² = 27.18

r² = 27.18 / π

r = √ (   27.18 / 3.14  )

r = 2.94 inches

Problem 2B:

Given:

Highest Ultimate load = 135,900 lb

max tensile strength (steel) = 50,000 lbs/in²

cross sectional area in inches² = (we are asked to find this)

Again simply substitute the above into the 2nd equation at the top:

Highest Ultimate load = max tensile strength x cross sectional area

135,900 = 50,000 x cross sectional area

cross sectional area = 135,900 / 50,000

cross sectional area = 2.718 in²