blfigueroa08
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write an equation that passes through (-2, - 11) and is perpendicular to x + 4y=8​

Sagot :

itsandypandy

Answer:

y = 4x - 3

Step-by-step explanation:

Firstly rearrange into the form y = mx + c;

⇒ [tex]y = -\frac{1}{4}x + 2[/tex]

Secondly, find the gradient of the line using the formula for perpendicular lines;

⇒ [tex]m_{1}m_{2} = -1[/tex]

⇒ [tex]-\frac{1}{4}m_{2} = -1[/tex]

⇒ [tex]m_{2} = 4[/tex]

Now substitute into the formula for a straight line;

⇒ [tex]y - y_{1} = m(x - x_{1})[/tex]

⇒ [tex]y + 11 = 4(x + 2)[/tex]

⇒ [tex]y = 4x - 3[/tex]

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