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Sagot :
The force that will balance the two forces is 6.4 N
Data obtained from the question
- Force 1 (F₁) = 4 N
- Force 2 (F₂) = 5 N
- Resultant force (F)
The resultant force, F can be obtained as follow:
F = √(F₁² + F₂²)
F = √(4² + 5²)
F = √(16 + 25)
F = √41
F = 6.4 N
Thus, the force that will balance the two forces is 6.4 N
See attached photo
Learn more about resultant force:
https://brainly.com/question/25239010
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The force that will counterbalance two forces 4.0 N and 5.0 N acting perpendicular to each other is a force of 6.4 N acting in an opposite direction to the resultant of the two forces.
Equilibrant of forces
- The equilibrant of two or more forces is that single force which will have the same effect as the resultant of two or more forces but which is acting in a direction opposite to that of the resultant force.
The Resultant of the two forces 4.0 N and %.0 N acting perpendicular to each other is calculated using the formula:
R² = A² + B²
where A and B are the two forces acting perpendicular to each other.
R² = 4² + 5²
R² = 41
R = 6.4 N
Therefore, the force that will counterbalance two forces 4.0 N and 5.0 N acting perpendicular to each other is a force of 6.4 N acting in an opposite direction to the resultant of the two forces.
Learn more about resultant and equilibrant forces at: https://brainly.com/question/8045102
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