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An object travels in a circular path of radius 5. 0 meters at a uniform speed of 10. Meters per second. What is the magnitude of the object's centripetal acceleration?.

Sagot :

Answer:

20 m/s^2

Explanation:

Use the relation a = v^2/r , where is the centripetal acceleration, v is speed of the object which is revolving in the circular path an r is the radius of the circular path.

Given v = 10 m/s , r = 5 m

a = 10 * 10/5

= 20 m/s ^2

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