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Prove : sina+tana/tana=1+cosa​

Sagot :

Answer:

See below

Step-by-step explanation:

[tex]\frac{sin\alpha+tan\alpha}{tan\alpha}[/tex]

[tex]\frac{sin\alpha}{tan\alpha}+\frac{tan\alpha}{tan\alpha}[/tex]

[tex]\frac{sin\alpha}{tan\alpha}+1[/tex]

[tex]\frac{sin\alpha}{\frac{sin\alpha}{cos\alpha}}+1[/tex]

[tex](\frac{sin\alpha}{1}*\frac{cos\alpha}{sin\alpha})+1[/tex]

[tex]cos\alpha+1[/tex]

Hence, [tex]\frac{sin\alpha+tan\alpha}{tan\alpha}=1+cos\alpha[/tex]