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What are the solutions of the equation mc001-1. Jpg?x = mc001-2. Jpgx = mc001-3. Jpgx = mc001-4. Jpgx = mc001-5. Jpg.

Sagot :

MrRoyal

The solutions to the equation are 19 and 31

Equation

The equation is given as:

[tex](x -25)^2=36[/tex]

Evaluating the equation

Take the square roots of both sides of the equation

[tex]x -25=\pm 6[/tex]

Add 25 to both sides of the equation

[tex]x =25\pm 6[/tex]

Split the above equation, as follows

[tex]x =25- 6, 25 + 6[/tex]

Evaluate both expressions

[tex]x =19,31[/tex]

Hence, the solutions to the equation are 19 ad 31

Read more about equations at:

https://brainly.com/question/13729904

Answer:

its A on edge 2022

Explanation:

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