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The energy transferred from the water in the kettle to the surroundings in 2 hours is 
46 200 J.Calculate the average power output from the water in the kettle to the surroundings in 2 hours.

Sagot :

onyebuchinnaji

The average power output from the water in the kettle to the surroundings in 2 hours is 6.42 W.

The given parameters:

  • Energy transferred, E = 46,200 J
  • Time, t = 2 hours

What is average power?

Average power is energy dissipated by an object over a given period of time.

The average power output from the water in the kettle to the surroundings in 2 hours is calculated as follows;

Power = Energy divided  by time

[tex]P = \frac{E}{t}[/tex]

  • t is time in seconds = 2 x 3600s = 7200 s

[tex]\\\\P = \frac{46,200}{7200} \\\\P = 6.42 \ J/s = 6.42 \ W[/tex]

Thus, the average power output from the water in the kettle to the surroundings in 2 hours is 6.42 W.

Learn more about average power here: https://brainly.com/question/1369261

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