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What is the solution of ? x = 2 x = 3 x = 2 or x = 3 no solution.

Sagot :

abidemiokin

The solution to  the given equation is x = 2 and x = 3

Given the equation;

  • [tex]x = 2 +\sqrt{x-2}[/tex]

Subtract 2 from both sides;

[tex]x = 2 +\sqrt{x-2}\\x - 2= 2 - 2+\sqrt{x-2}\\x - 2 = \sqrt{x-2}\\[/tex]

Take the square of both sides:

[tex](x-2)^2 =(\sqrt{x-2} )^2\\(x-2)^2 = x-2\\(x-2)^2 - x+2 = 0\\(x-2)^2-1(x-2) = 0\\x-2[x-2-1] = 0\\(x-2)(x-3) =0\\x = 2 \ or \ 3[/tex]

Hence the solution to  the given equation is x = 2 and x = 3

Learn more on rational equations here: https://brainly.com/question/4419050

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