Westonci.ca is the best place to get answers to your questions, provided by a community of experienced and knowledgeable experts. Get detailed answers to your questions from a community of experts dedicated to providing accurate information. Explore comprehensive solutions to your questions from knowledgeable professionals across various fields on our platform.

Two pumps at a local water facility can only
run individually. They will run for at least 18
hours in a day but obviously no more than 24
hours in a day. Pump 1 can move 120 gallons
per hour while Pump 2 can move 200 gallons
per hour. In total the two pumps must move at
least 3,000 gallons of water per day. If x
represents the number of hours that Pump 1
runs and y represents the number of hours that
Pump 2 runs, write a system of inequalities
that models all conditions.

Sagot :

According to the information given, the system of inequalities that models the situation is given by:

  • [tex]x + y \geq 18[/tex]
  • [tex]x + y \leq 24[/tex]
  • [tex]120x + 200y \geq 3000[/tex]

System of inequalities:

For the system, the variables are:

  • x is the number of hours that Pump 1 runs.
  • y is the number of hours that Pump 2 runs.

They will run for at least 18  hours in a day but obviously no more than 24  hours in a day, hence:

[tex]x + y \geq 18[/tex]

[tex]x + y \leq 24[/tex]

Pump 1 can move 120 gallons  per hour while Pump 2 can move 200 gallons  per hour. In total the two pumps must move at  least 3,000 gallons of water per day, hence:

[tex]120x + 200y \geq 3000[/tex]

You can learn more about system of inequalities at https://brainly.com/question/14361489