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Sagot :
Answer:
10 Milk chocolates
8 dark chocolates
6 white chocolates
24 TOTAL
\frac{10}{24} Probability that Hanissa choose a milk chocolate
Now, since she has already eaten one chocolate, then what's left is 23 chocolates.
So, since the second one should be a white chocolate and there are 6 of them, then
\frac{6}{23} - probability of choosing a white chocolate.
Then, multiply,
( \frac{10}{24} )( \frac{6}{23} )= \frac{60}{552} or \frac{5}{46}
Answer: 5/46 or 10.87%
Step-by-step explanation: no explanation:
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