caidyn0
Answered

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Sagot :

Step-by-step explanation:

If we have a exponent.

[tex] {x}^{m} \times {x}^{n} = x {}^{m + n} [/tex]

So we just have

[tex]3 \times 3 \times 5 = 45[/tex]

[tex]x {}^{ - 3} \times x {}^{ - 8 {}^{ } } = x {}^{ - 11} [/tex]

Then we get

[tex] {v}^{ - 9} \times v = v {}^{ - 8} [/tex]

[tex]w{}^{ - 2} \times x {}^{ 2} = w {}^{0} [/tex]

Which is just 1.

So we got,

[tex]45 {x}^{ - 11} v {}^{ - 8} [/tex]

Now, we can just put this under the mumberator since this negative.

[tex] \frac{45}{ {x}^{11} v {}^{8} } [/tex]

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