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how to solve this (b) ???​

How To Solve This B class=

Sagot :

(b). → Simplify: [{5^(x-+1) + 5^x}/{6×5^x}]

= [{5^(x+1+x)}/{6×5^x}]

= [{5^(2x+1)}/{6×5^x}]

= [{5^(2x+1)}/{6×5^x}]

= [{5^(2x+1-x)}/6]

= [{5^(x+1)}/6]Ans.

(c). 4a³b²

= 4(3)³(-2)²

Since, a = 3 and b = -2.

so,

= 4(3*3*3)(-2*-2)

= 4(27)(4)

= 108(4)

= 432Ans.

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