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Sagot :
Answer:
Force on ladder 1 (left): 30.4 N
Force on ladder 2 (right): 60.8 N
Step-by-step explanation:
Given the left ladder is 1 then right ladder is 2
So distance from ladder 1 to center of mass d1 is 1.00 m
then distance from ladder 2 to center of mass d2 is 0.5 m (1.50 - 1.00)
The torque in ladder 1 is t1 while torque in ladder 2 is t2
so t1 = t2
since t = Fd
t1 = t2
F1d1 = F2d2
F1 = 0.5F2
since all equilibrium is 0, the sum of all forces
Force on ladder = F1 + F2
91.2 = F1 + F2
since F1 = 0.5F2
91.2 = 0.5F2 + F2
F2 = 91.2/1.5 = 60.8
F1 = 0.5F2 = 0.5(60.8) = 30.4
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