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Sagot :

  • Let us consider the length of the cube A as 1 mm and that of cube B as 3 mm.
  • Surface area of the cube A = 6 mm^2.
  • Volume of the cube A = 1 mm^3
  • Ratio of the cube A = 6: 1
  • Surface area of the cube B = 6×3^2 mm^2 = 54 mm^2
  • Volume of the cube B = 27 mm^3
  • Ratio of the cube B = 54: 27 = 2: 1.
  • So, cube B has lesser surface volume ratio.

Answer:

Cell A has a higher surface area to volume ratio than cell B.

Hope you could understand.

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