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Х(2x+3) + (х-3)(х - 4)


Sagot :

Answer:

[tex]\huge\boxed{\sf 3x^2-4x+12}[/tex]

Step-by-step explanation:

[tex]=x(2x+3)+(x-3)(x-4)\\\\Using \ distributive \ property\\\\=(x)(2x)+(x)(3)+x(x-4)-3(x-4)\\\\=2x^2+3x+x^2-4x-3x+12\\\\Combining \ like \ terms\\\\= 2x^2+x^2+3x-3x-4x+12\\\\= 3x^2-4x+12\\\\\rule[225]{225}{2}[/tex]

Hope this helped!

~AH1807