The two balls will hit the water at the same time, but Jacqueline's will travel further.
The given parameters:
- Horizontal velocity of Liz's ball, v₁ = 20 m/s
- Horizontal velocity of Jacqueline's ball, v₂ = 30 m/s
- Initial vertical velocity of both balls, [tex]V_y_i[/tex] = 0
The time for both balls to hit the water is calculated as follows;
[tex]h= V_y_i + \frac{1}{2} gt^2\\\\h = 0 + \frac{1}{2} gt^2\\\\h = \frac{1}{2} gt^2\\\\t = \sqrt{\frac{2h}{g} }[/tex]
Thus, both balls will hit the water at the same time, since the time of motion is independent of the horizontal velocity.
The horizontal distance traveled by each ball is calculated as follows;
[tex]d = v_x \times t\\\\Liz: \ \ d = 20t\\\\Jacqueline: \ d = 30t[/tex]
Thus, we can conclude that the two balls will hit the water at the same time, but Jacqueline's will travel further.
Complete question is below:
Liz and Jacqueline each hit a golf ball off the top of an ocean cliff. Liz's ball has a horizontal velocity of 20m/s, while Jacqueline's has a horizontal velocity of 30 m/s. both balls are hit at the same time, and neither has any initial vertical velocity. which of the following statements are is true?
a. Jacqueline's ball will hit the water first, bit Liz's will travel further
b. the two balls will hit the water at the same time, but Jacqueline's will travel further.
c. the two halls will travel the same distance and hit the water at the same time.
d. Liz's ball will hit the water first, but Jacqueline's will travel further.
Learn more about time of vertical motion here: https://brainly.com/question/4106229
